the velocity of an object changes from v1=10i^+4j^+2k^ to v2=4i^+2j^+3k^in 5 sec find the magnitudevof average acceration
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Answered by
417
Acceleration = (v₂ - v₁) / T
= (4i + 2j + 3k - 10i - 4j - 2k) / 5
= (-6i - 2j + k) / 5
= -1.2i - 0.4j + 0.2k
Magnitude = √(1.2² + 0.4² + 0.2²) = 1.28 m/s²
= (4i + 2j + 3k - 10i - 4j - 2k) / 5
= (-6i - 2j + k) / 5
= -1.2i - 0.4j + 0.2k
Magnitude = √(1.2² + 0.4² + 0.2²) = 1.28 m/s²
Answered by
114
The velocity of an object changes from
v1=10i^+4j^+2k^ to v2=4i^+2j^+3k^in 5 sec
and the magnitude of average acceleration will be
Acceleration = (v₂ - v₁) / T = (4i + 2j + 3k - 10i - 4j - 2k) / 5 = (-6i - 2j + k) / 5 = -1.2i - 0.4j + 0.2k
and Magnitude = √(1.2² + 0.4² + 0.2²) = 1.28 m/s².
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