Physics, asked by vipashish, 8 months ago

The velocity of an object increases at a constant rate from 20ms-1 to 50ms-1

in 10s. Find the

acceleration.​

Answers

Answered by simmyrajput2002
3

Explanation:

Given Initial velocity u = \rm 20m{s}^{-1}20ms

−1

Final velocity v = \rm 50m{s}^{-1}50ms

−1

Time t = 10s

\rm \: Acceleration \: a = \frac{v - u}{t}Accelerationa=

t

v−u

\rm \: a= \frac{50m {s}^{ - 1} - 20m {s}^{ - 1} }{10s}a=

10s

50ms −1

−20ms −1

\rm \: a= \frac{30m {s}^{ - 1} }{10s}a=

10s

30ms

−1

Answered by Anonymous
2

Answer:

62cm

Explanation:

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