The velocity of an object is given by V= 4t³-2t²+5t,Find the acceleration at t=1,Find the distance if v=0 at t=1
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Answer:
Given displacement x=5+3t+2t
2
Differentiating the above equation with respect to time t we get velocity of the body
v=
dt
dx
=3+4t
Now again differentiating the velocity with respect to time we get acceleration
a=
dt
dv
=4
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