Question

the velocity of an object of mass 100 kg is increased from 5m/s to 8m/s in 6s find out the amount of force acting on it ?​

Answer 1

hope it help you...........

Answer 2

$\displaystyle\large\underline{\sf\red{Given}}$

✭ Initial Velocity (u) = 5 m/s

✭ Final Velocity (v) = 8 m/s

✭ Time (t) = 6 sec

✭ Mass (m) = 100 kg

$\displaystyle\large\underline{\sf\blue{To \ Find}}$

◈ The force applied?

$\displaystyle\large\underline{\sf\gray{Solution}}$

So here we shall first find the Acceleration of the body with the help of the first Equation of motion, then with the help of Newton's second law we shall find the force applied on the body!!

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$\underline{\bigstar\:\textsf{According to the given Question :}}$

So here the acceleration of the body will be given by,

➝ $\displaystyle\sf v = u+at$

➝ $\displaystyle\sf 8 = 5+a\times 6$

➝ $\displaystyle\sf 8-5 = 6a$

➝ $\displaystyle\sf 3 = 6a$

➝ $\displaystyle\sf \dfrac{3}{6} = a$

➝ $\displaystyle\sf \orange{Acceleration = 0.5 \ m/s^2}$

Now the force applied on the body will be equal to,

➳ $\displaystyle\sf F = ma$

➳ $\displaystyle\sf F = 100\times 0.5$

➳ $\displaystyle\sf F = 10\times 5$

➳ $\displaystyle\sf \pink{Force = 50 \ N}$

$\displaystyle\therefore \: \underline{\sf{Force \ applied \ is} \ \textbf{50 N}}$

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☯ $\displaystyle\sf \underline{\sf Know \ More}$

⪼ $\displaystyle\sf s = ut+\dfrac{1}{2} at^2$

⪼ $\displaystyle\sf v^2-u^2 = 2as$

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