Question

the velocity of an object of mass 50 kg increase from 3 m s^ to 12 m s^ - 1. What will be the force required for this?

Answer 1

Given the initial velocity = u = 3 m/s

Final velocity = v = 12 m/s

There for acceleration = v-u =9 m/s

Given mass = 50 kg

We know that,

F =ma subsituting we get,

F= 50 × 9

F= 450N

Answer 2

Given that,

Mass of the object, m = 50 kg

Initial speed of the object, u = 3 m/s

Final velocity of the object, v = 12 m/s

Let us assume that the time, t = 1 s

To find,

The force required for this.

Solution,

Newton's second law of motion gives the magnitude of force. It say that the product of mass and acceleration is equal to force. So,

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{50\times (12-3)}{1}\\\\F=450\ N$

So, the force of 450 N is required for this.

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