Question

The velocity of an object of mass 50 kg increases from 3ms-1 to 12ms-1. What will be the force required for this.

Answer 1

F=m(v"-v')/t

F=50(12-3)/1

F=450N

t is time considered as 1 sec.as you didnot mention.

hope the answer is helpful.

Answer 2

The force required for this is $(\dfrac{450}{t})\ N$.

Explanation:

Given that,

Mass of the object, m = 50 kg

Initial speed of the object, u = 3 m/s

Final speed of the object, v = 12 m/s

We need to find the force required for this. We know that the force is given by the product of mass and its acceleration i.e.

$F=ma\\\\F=\dfrac{m(v-u)}{t}$

t is the time taken to change its speed from 3 m/s to 12 m/s

$F=\dfrac{50\times (12-3)}{t}\\\\F=(\dfrac{450}{t})\ N$

So, the force required for this is $(\dfrac{450}{t})\ N$.

Learn more,

Force

https://brainly.in/question/15936812