Question

the velocity of an object of mass 50kg increases from 3m/s to 12 m/s. What will be the force required for this? ​

Answer 1

Answer:

$450t^{-1} N$

Explanation:

The force applied= Mass × acceleration

                            = mass × ( $\frac{v-u}{t}$)

 

Where u is initial velocity and v is final velocity and t is the time taken to change the velocity from u to v.

Plunging in the values we have,

Force = 50 kg × $\frac{12-3}{t} ms^{-2}$  

           = 50×$\frac{9}{t}$ N

            = $\frac{450}{t} N$

Therefore the resulting value will be time dependent (as always, duh) in the form of $450t^{-1} N$ .

           

Answer 2

Answer:

ok

Explanation:

thanks great

excellent