Question

the Velocity of an object with change with time and relation is gien below v= 2t+3t^2 calculate position of the object from origin at t=2 s

Answer 1

V=dx/dt
x = (3t^2+2t) ( given)
on differentiation
V= 6t+2
Hence when t=2
Then v=6(2) + 2
=14 m/s
Hence displacement =v×t
=14×2
=28m