Question

the velocity of any particle is related with its displacement as x=√v+1 calculate acceleration at x=5 m​

Answer 1

Explanation:

given equation is x=√v + 1

So v= (x - 1)^2 differentiating the equation with respect to time we get

a=2(x - 1)v {a is acceleration}

Now v at x=5 units is 16 units per second

So a=2×4×16 = 128 units per second square

Answer 2

Answer:

240m/s^2

Explanation:

X= $\sqrt{v+1}$        squaring both sides

x^2= v+1

v= x^2- 1

Now, a= dv/dt, on differentiating v= x^2- 1, we get 2x*dx/dt (using chain rule)

dx/dt= v, so in place of dx/dt we can write x^2- 1

therefore, a= 2x*(x^2-1)

x=5m/s^2

so, a= 2(5)* (25-1)= 10*24= 240m/s^2

so a= 240m/s^2