Physics, asked by dtanuja122, 7 months ago

the velocity of boat relative to water is 4m/sec the velocity of water relative to ground is 8m/sec in which direction the boat man aims the boat to cross the river in minimum drift method ​

Answers

Answered by rawatricky17
11

Explanation:

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Answered by bharathparasad577
0

Answer:

Concept:

If we have the velocity of the boat and the velocity of the river, then we can find the angle for which drift is minimum for that particular velocity of the boat.

Explanation:

Given:

The velocity of the boat relative to water is 4m/sec

The velocity of water relative to the  ground is 8m/sec

Find:

In which direction the boatman aims the boat to cross the river in the minimum drift method ​

Solution:

Here, $v_{b / r} is the Velocity of the boat relative to the river

         v_{r} is the Velocity of the river

         v_{b} is the Velocity of the boat

                         $$\begin{aligned}&\overrightarrow{v_{b / r}}=\overrightarrow{v_{b}}-\overrightarrow{v_{r}} \\&\vec{v}_{b}=\vec{v}_{b / r}+\vec{v}_{r} \\&\left(v_{b}\right)_{x}=\left(v_{b / r}\right)_{x}+\left(v_{r}\right)_{x} \\&\left(v_{b}\right)_{x}=v_{r}-v_{b / r} \sin \theta . \\&x=\left(v_{r}-v_{b / r} \sin \theta\right) t\end{aligned}$$--------(1)

                        \left(v_{b}\right)_{y}=\left(v_{b / r}\right)_{y}+\left(v_{r}\right)_{y}$\\\\$\left(v_{b}\right) y=v_{b / r} \cos \theta$$\Rightarrow d=v_{b / r} \cos \theta t \\\\\Rightarrow t=\frac{d}{v_{b / r} \cos \theta}$---------(2)

By using the Equations (1) and (2)

                    $$\begin{aligned}&\Rightarrow x=\frac{d}{v_{b / r}}\left[v_{r} \sec \theta-v_{b / r} \tan \theta\right]\\&\frac{d x}{d t}=0 \Rightarrow \frac{d}{v_{b / r}}\left[v_{r} \sec \theta \tan \theta-v_{b / r} \sec ^{2} \theta\right]=0 .\\&\Rightarrow V_{r} \sec \theta \tan \theta=v_{b / r} \sec ^{2} \theta \sec \theta\\&\Rightarrow v_{r} \frac{\sin \theta}{\cos \theta}=v_{b / r} 1 / \cos \theta \Rightarrow \sin \theta=\frac{v_{b / r}}{V_{r_{}}}\end{aligned}$$

                          sin\theta = $\frac{4}{8} $

                          sin\theta = $\frac{1}{2}

                          $sin\frac{1}{2} = 30°

The angle for which drift is minimum for that particular velocity of the boat is 30°.

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