The velocity of body of mass 10kg increases from 5m/s to8m/s when a force acts on it for 2s. Find What is the value of the force.
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F= ma. a=v2-v1/t. F=10 * ((8-5)/2). F=10*(3/2). F=5*3= 15N
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m=10
v1=5
v2=8
∆v=v2-v1=3
F=m*a
a=∆v/∆t
t1=0
t2=2
∆t=t2-t1=2
thrfr a=3/2
thrfr F=10*3/2=15N
v1=5
v2=8
∆v=v2-v1=3
F=m*a
a=∆v/∆t
t1=0
t2=2
∆t=t2-t1=2
thrfr a=3/2
thrfr F=10*3/2=15N
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