Question

The velocity of body of mass 20 kg decreases from 20 m/s to 10 m/s in a distance of 10 m. force on the body is?

Answer 1

Answer:

-300 N

Explanation:

v^2 = u^2 + 2as

(10)^2 = (20)^2 +2x10 a

100 = 400 + 20a

20a = -300

a=-15

now , F=ma

F = 20x -15

F= -300 N