Question

the velocity of bullet becomes halved while travelling through a distance of 6cm. Further distance it has to travel before coming to rest

along with procedure plz 

Answer 1

initial velocity = u  final velocity = v = u/2
distance = s = 6 cm 
apply   v² = u²  + 2 a s  =>  u²/4 = u² + 2 a 6 => -3/4 u² = 12 a
  a = - 1/16 u²    a is -ve and so it is slowing down
     apply again v² = u² + 2a S
     now v =0.  initial speed = u²/4    So  0 = u²/4 - 2  1/16  u² S
     S =  2 cm

Answer 2

because velocity is inversely proportional to the distance travelled