Question

the velocity of car decrease from 43km/h to 25km/h in 10s find its retardation​

Answer 1

Answer:

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Answer 2

Answer:

The velocity time and acceleration time is given by

at = v -u  

Where a is acceleration

v is final velocity and u is initial velocity

t is the time taken

So,

From the data  

u=43 km/hr

u=43/3600  km/sec

v=25 km/hr

v=25/3600 km/sec

a=(-43/3600 + 25/3600)/10

a= -0.0005 km/sec²

a= -0.5 m/sec²

So,

The retardation is 0.5 m/sec²  

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Explanation: