the velocity of car increase from 30kmph to 45kmph in 5minutes. assuming the acceleration to be uniform calculate the distance travelled
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distance travelled = 3125 m
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make my answer brainliest if it helps...
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1
initial velocity of car is equal to 30 kmph and final velocity of car is equal to 45 kmph
time is equal to 5 minutes is equal to 1 / 12 hour
so according to first kinematics equation we can say that
v=u+at
45=30+(A)1/12
45-30=1/12A
15=1/12A
A=15*12km/hr²
a=180km/hr²
time is equal to 5 minutes is equal to 1 / 12 hour
so according to first kinematics equation we can say that
v=u+at
45=30+(A)1/12
45-30=1/12A
15=1/12A
A=15*12km/hr²
a=180km/hr²
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