Question

The velocity of car increases from 50 km per hour 90 km per hour in 0.3 minute calculate the acceleration produced the velocity of car increases from 30 km per hour 90 km per hour in 0.2 minute calculate the acceleration produced​? ​

Answer 1

Answer:

• 8000km/h² is the required acceleration in case 1st.
• 18000 km/h² is the required acceleration in case 2nd of the car .

Step-by-step explanation:

According to the Question

It is given that ,

• Initial velocity ,u = 30km/h
• Final velocity ,v = 90km/h
• Time taken ,t = 0.2min

we need to calculate the acceleration of the car .

Firstly we convert the unit here

Minutes into hour

➻ 1 hour = 60min

➻ 1min = 1/60 hour

➻ 0.2min = 1/60× 2/10

➻ 0.2 min = 2/600 = 1/300 hour.

As we know that acceleration is defined as the rate of change in velocity at per unit time.

• a = v-u/t

where,

a denote acceleration

v denote final velocity

u denote initial velocity

t denote time taken

Substitute the value we get

➻ a = 90-30/ ÷ 1/300

➻ a = 60×300/1

➻ a = 18000km/h².

• Hence, the acceleration of the car is 18000km/h².

_______________________

For 1st case :-

According to the Question

• Initial velocity ,u = 50km/h
• Final velocity ,v = 90km/h
• time taken ,t = 0.3min

we need to calculate the acceleration of the car

Conversion of unit

0.3min = 3/600 = 1/200 h

• a = v-u/t

substitute the value we get

➻ a = 90-50 ÷ 1/200

➻ a = 40×200

➻ a = 8000km/h²

• Hence, the acceleration in 1st case is 8000km/h².

Answer 2

Answer:

Question No 1 :-

• The velocity of car increases from 50 km/h to 90 km/h in 0.3 minutes. Calculate the acceleration produced ?

Given :-

• The velocity of car increases from 50 km/h 90 km/h in 0.3 minutes.

To Find :-

• What is the acceleration produced.

Formula Used :-

$\clubsuit$ First Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v =\: u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Solution :-

First, we have to convert time minutes into hours :

$\implies \sf Time =\: 0.3\: minutes$

$\implies \sf Time =\: \dfrac{0.3}{60}\: hours$

$\implies \sf\bold{\purple{Time =\: 0.005\: hours}}$

Now, we have to find the acceleration produced :

Given :

• Initial Velocity (u) = 50 km/h
• Final Velocity (v) = 90 km/h
• Time (t) = 0.005 hours

According to the question by using the formula we get,

$\longrightarrow \sf 90 =\: 50 + a(0.005)$

$\longrightarrow \sf 90 =\: 50 + 0.005a$

$\longrightarrow \sf 90 - 50 =\: 0.005a$

$\longrightarrow \sf 40 =\: 0.005a$

$\longrightarrow \sf \dfrac{40}{0.005} =\: a$

$\longrightarrow \sf 8000 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 8000\: km/h^2}}$

${\small{\bold{\underline{\therefore\: The\: acceleration\: produced\: is\: 8000\: km/h^2\: .}}}}$

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Question No 2 :-

• The velocity of car increases from 30 km/h to 90 km/h in 0.2 minutes. Calculate the acceleration produced.

Given :-

• The velocity of car increases from 30 km/h to 90 km/h in 0.2 minutes.

To Find :-

• What is the acceleration produced.

Formula Used :-

$\clubsuit$ First Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v =\: u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Solution :-

First, we have to find the time minutes into hours :

$\implies \sf Time =\: 0.2\: minutes$

$\implies \sf Time =\: \dfrac{0.2}{60}\: hours$

$\implies \sf\bold{\purple{Time =\: 0.003\: hours}}$

Now, we have to find acceleration produced :

Given :

• Initial Velocity (u) = 30 km/h
• Final Velocity (v) = 90 km/h
• Time (t) = 0.003 hours

According to the question by using the formula we get,

$\longrightarrow \sf 90 =\: 30 + a(0.003)$

$\longrightarrow \sf 90 =\: 30 + 0.003a$

$\longrightarrow \sf 90 - 30 =\: 0.003a$

$\longrightarrow \sf 60 =\: 0.003a$

$\longrightarrow \sf \dfrac{60}{0.003} =\: a$

$\longrightarrow \sf 20000 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 20000\: km/h^2}}$

${\small{\bold{\underline{\therefore\: The\: acceleration\: produced\: is\: 20000\: km/h^2\: .}}}}$