Chemistry, asked by shivasinghmohan629, 4 hours ago

The velocity of car increases from 50 km per hour 90 km per hour in 0.3 minute calculate the acceleration produced the velocity of car increases from 30 km per hour 90 km per hour in 0.2 minute calculate the acceleration produced​? ​

Answers

Answered by anjalirehan04
3

u = 50 km/h = 250/18 m/s = 13.88 m/s

v = 90 km/h = 25 m/s

t = 0.3 minute = 0.3*60 s = 18 s

a = (v - u)/t = (25 - 13.88)/ 18 = 11.12/18 = 0.6177 m/s^2

Case 2:

u = 30 km/h = 25/3 m/s = 8.33 m/s

v = 90 km/h = 25 m/s

t = 0.2 = 0.2*60 = 12 s

a = (v - u)/t = (12 - 8.33)/12 = 3.67/12 = 0.3058 m/s^2

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Answered by DakshRaj1234
2

Answer:

u = 50 km/h = 250/18 m/s = 13.88 m/s

Chemistry

5 points

4G 44

v = 90 km/h = 25 m/s

t = 0.3 minute = 0.3*60 s = 18 s

a = (v - u)/t = (25-13.88)/ 18 = 11.12/18 = H 0.6177 m/s^2

Case 2:

u = 30 km/h = 25/3 m/s = 8.33 m/s

v = 90 km/h = 25 m/s

t = 0.2 = 0.2*60 = 12 s

a = (v - u)/t = (12-8.33)/12 = 3.67/12 =

0.3058 m/s^2

please mark me brain mark list

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