Question

The velocity of car increases uniformly from 5ms-1 to 10ms-1 ,when it travels 50m. Find acceleration af car​

Answer 1

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Given that,

v = 20 m/s

u = 5 m/s

s = 50 m

We need to find : Acceleration (a) of the car.

Using the third equation of motion : v² - u² = 2as.

⇒ (10)² - (5)² = 2a*50

⇒ 100 - 25 = 100a

⇒ 75 = 100a

⇒ a = 75/100

⇒ a = 0.75 m/s²

Hence, Acceleration of the car is 0.75 m/s².

Answer 2

Given :

• Initial Velocity (u) = 5m/s
• Final Velovity (v) = 10m/s
• Distance Travelled (s) = 50m.

To Find :

• Acceleration (a) of the car.

Solution :

For Finding the acceleration :

Using 3rd Equation :

$\longmapsto\tt\boxed{{v}^{2}-{u}^{2}=2as}$

Putting Values :

$\longmapsto\tt{{(10)}^{2}-{(5)}^{2}=2a(50)}$

$\longmapsto\tt{100-25=100a}$

$\longmapsto\tt{75=100a}$

$\longmapsto\tt{a=\cancel\dfrac{75}{100}}$

$\longmapsto\tt\bold{a=0.75{m/s}^{2}}$

So , The Acceleration of the car is 0.75m/s²...

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Acceleration :

The rate of change of the velocity of an object is known as Acceleration.

Formula of Acceleration :

$\longmapsto\tt\boxed{a=\dfrac{v-u}{t}}$

Here :

• v = final velocity
• u = initial velocity
• t = time taken

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