Question

the velocity of car is increased from 54 km/hr to 72 km/ hr. how much work is done if mass of the car is 1500kg?

Answer 1

Heya.......!!!

_______________________________


Given In the Question :-

•---»» Initial Velocity = 54 km/hr = 15 m/s
•---»» Final Velocity = 72 Km/hr = 20 m/s

•---»» Mass of car = 1500 Kg

We have to take out work done .

:-

=> Initial Kinetic Energy = 1/2×m×u^2

=> 1/2 × 1500 × 15×15

→ Initial Kinetic Energy => 168750 J


=> Final Kinetic Energy = 1/2 ×m× v^2

=> 1/2 × 1500 × 20×20

→ Final Kinetic Energy => 300000 J


We know that Work done is = Change In Kinetic Energy ( ∆ KE )

=> ∆ KE ( change in kinetic Energy ) = 300000 - 168750 => 131250 J

♦Hence The Work Done is → 131250 J



==============================

Hope It Helps You ☺

Answer 2

Hola!

Given
Mass of the car = 1500kg
Initial velocity of the car (u) = 54km/hr = 15m/s
Final velocity of the car (v) = 72km/hr = 20m/s

Initial K.E
$= \frac{1}{2} m { u}^{2}$
= 1/2 × 15000 × 15 × 15
= 168750 J

Final K.E
$= \frac{1}{2} mv {}^{2}$
= 1/2 × 15000 × 20 × 20
= 300000 J

=> Work done = Final K.E - Initial K.E
=> W = 300000 J - 168750J
=> W = 131250

Thus,
The total work done is 131250 Joules.

Peace out ✌️