Question

The velocity of car reduced 20 m/s from 40 m/s in 5 second the retractation of the car is

Answer 1

Answer:

The velocity of car reduced 20 m/s from 40 m/s in 5 second the retractation of the car is $-4 m/s^{2}$

Explanation:

Given,

Initial velocity (u) =  40 m/s

Final velocity (v)  =  20 m/s

Time taken (t)      = 5 sec

Acceleration is the rate of change of velocity with respect to time.

Negative acceleration of the car is called retardation or deceleration of the car.

We an express the acceleration  (a) as,

$a = \frac{v - u}{t}$

substituting values to the above equation,

a = $\frac{20-40}{5}$ = $\frac{-20}{5} = -4 m/s^{2}$

Ans :

Retardation of the car = $-4 m/s^{2}$