Question

The velocity of
care increases curiformely
from 5 ms to 10ms -1when it
travels 50m. find acceleration
of
Cour.​

Answer 1

We need to find acceleration

v^2 - u^2 = 2as

100 - 25 = 2 x 50 x a

75/100 = a

a = 0.75 m/s

Answer 2

Answer:

Given :-

u = 5m/s

v = 10m/s

To find :-

acceleration.

solution:-

v = d/ t

10 m/s - 5 m/s = 50 / t

5 = 50 / t

5 t = 50

t = 50/5

t = 10 sec

a = v - u / t

a = 10 - 5 / 10

a = 5 / 10

a = 0.5 m/s

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