Chemistry, asked by minnichinnureddy, 9 months ago


The velocity of electron in the first Bohr orbit of a hydrogen atom is 2.19x10ʻm.sec. Its velocity is the second orbit would be

Answers

Answered by ankitsharma7734
2

Answer:

1.09 *10^6 m/s

Explanation:

the velocity of electron in orbit = 2.19 * 10^6 * Z/n

where , Z  = atomic number of H - atom and 'n' = no. of orbit

velocity of electron in 2 orbit =  2.19 * 10^6 * 1/2 = 1.09 m/s

Similar questions