The velocity of electron in the first Bohr orbit of a hydrogen atom is 2.19x10ʻm.sec. Its velocity is the second orbit would be
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Answer:
1.09 *10^6 m/s
Explanation:
the velocity of electron in orbit = 2.19 * 10^6 * Z/n
where , Z = atomic number of H - atom and 'n' = no. of orbit
velocity of electron in 2 orbit = 2.19 * 10^6 * 1/2 = 1.09 m/s
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