The velocity of electron in the ground state of H atom is 2.185x10^8 cm/sec. The
velocity of electron in the second orbit of Li2+ ion in cm /sec would be
(A) 3.276x108 (B) 2.185x108
(C) 491x10*
(D) 1.638x10°
Answers
Answered by
0
Answer:
The velocity of electron in the ground state of H atom is 2.185x10^8 cm/sec. The
velocity of electron in the second orbit of Li2+ ion in cm /sec would be
(A) 3.276x108 (B) 2.185x108
(C) 491x10*
(D) 1.638x10°
Please Mark As Brainliest
Similar questions