Chemistry, asked by Bandaysuhail, 1 year ago

the velocity of electron in third excited state of be3+

Answers

Answered by krittika03
44

here's your answer..

V=(2.188×10^6) × Z/n m/s

=(2.188×10^6) × 4/4 m/s

=(2.188×10^6) m/s

Answered by Tringa0
15

Answer:

The velocity of electron in third excited state of Be^{3+} is:

2.18\times 10^6 m/s.

Explanation:

Velocity of an electron in nth shell of an hydrogen like atom was given Bohr as:

V_n=\frac{2.18\times 10^6\times Z}{n} (m/s)

Z = atomic number of atom

n = Number of shell

The velocity of electron in third excited state of Be^{3+}:

1 → 4

V_4=\frac{2.18\times 10^6\times 4}{4} m/s=2.18\times 10^6 m/s

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