Question

The velocity of ground to ground projectile when it hits the ground is 3i-4j.taking the point of projection as origin ,initial velocity of projection is

Answer 1

Answer:

v = (Vx^2 + Vy^2)^1/2 = (9 + 16)^1/2 = 5

Since the projectile follows a parabolic path the speed of the projectile reaching the ground equals the initial speed and the velocity would b

3 i + 4 j

The horizontal velocity is unchanged and the vertical velocity is equal but opposite in sign to the vertical velocity of projection.