The velocity of light in a medium is 1.5 x 108 m/s. the critical angle of the medium for a ray going from the medium into air is:
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Answer:
30 degrees
Explanation:
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Given:
- The velocity of a medium = 1.5 × m/s
To Find:
- The critical angle of the medium for a ray going from the medium to air.
Solution:
The velocity of light in air = 3 × m/s
By snell's law we know that,
sin (i)/sin(r) = = → {equation 1}
On substituting the values in equation 1 we get,
⇒ sin (c)/1 = (1.5×)/(3 × ) {sin(r) = 1 since sin (90°) = 1}
⇒ sin (c)/1 = 1/2
⇒ sin (c) = sin (30°) { sin 30° = 1/2}
⇒ c = 30°
∴ The critical angle of the medium for a ray going from the medium to air = 30°
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