Question

The velocity of light in air is 3 * 108 ms-1 and that in water is 2.2 * 108 ms" . The polarising angle of incidence is
(a) 45°
(b) 50°
(c) 53.74°
(d) 63

Answer 1

Answer:I'M NOT SURE

Tan ib=refractive index

      refractive index=3/2.2=1.3

       Tan ib=1.3

              ib=(Tan)^-1(1.3)

Explanation:

Answer 2

Explanation:

The refractive index of water, μ=

Speed of light in air/speed of light in water

= 3*10^8/2.2*10^8

=1.36

From Brewster's Law:-

tan ip=μ=1.36

∴ip=tan-¹(1.36) =53.74°

SO, OPTION (C) IS THE CORRECT ANSWER......

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