Question

The Velocity of light in air is 3x108ms and the velocity of light in a medium is 2x108mst. The critical angle for the pair is 1÷sin​

Answer 1

Step-by-step explanation:

Velocity of light in a medium =

R.I.ofmedium

velocityoflightinair

2×10

8

m/s =

μ

3×10

8

m/s

μ=

2

3

Critical angle:

sinθ

C

=

μ

2

μ

1

sinθ

C

=

3/2

1

⇒θ

C

=sin

−1

(2/3)