Question

The velocity of light in glass whose refractive index with respect to air is 1.5 is 2×10^8 m/s. In a certain liquid the velocity of light is found to be 2.5×10^8 m/s . Find the refractive index of liquid with respect to air​

Answer 1

Answer:

• Refractive index of liquid with respect to air is 1.2.

Step By Step Explanation:

Given:

Refractive index of glass (n₁) = 1.5

Velocity of light in glass (v₁) = 2 × 10⁸ m/s.

Velocity of light in liquid (v₂) = 2.5 × 10⁸ m/s.

To Find:

• Refractive index of liquid with respect to air. (n₂)

Now, we know that

=> Refractive index = (Velocity of light)/(Velocity of light in medium)

=> n₁/n₂ = v₂/v₁

=> n₂ = v₁ n₁/v₂

Now, put the values,

=> n₂ = (2 × 10⁸ × 1.5)/(2.5 × 10⁸)

=> n₂ = (3 × 10⁸)/(2.5 × 10⁸)

=> n₂ = 3/2.5

=> n₂ = 1.2

Hence, refractive index of liquid with respect to air is 1.2.

Answer 2

$</p><p>\tt{\pink{\huge{Hello!!!}}}$

$</p><p>\tt{\green{Given \: - }}$

$\tt{ \purple{v _{g} \: = \: 2 \times {10}^{8 } \: m/s}}$

$\tt{ \orange{c \: = \: 3 \times {10}^{8 } \: m/s}}$

$\tt{ \blue{ \nu _ {g} \: = \: 1.5 \: }}$

$\tt{ \red{ { \rho _ {g}} \: = \: \frac{c}{v _ {g}} }}$

$\tt{ \purple{v _{l} \: = \: 3 \times {10}^{8 } \: ms}}$

$\tt{ \pink{ { \rho _ {L}} \: = \: \frac{c}{v _{L}} = \: 1.2}}$