Question

The velocity of light in medium A is 300 km/sec and that in medium B is 200 km/sec.Calculate the refractive index of medium A with respect to medium B.(Answer should be in simplest fraction)
ans asap

Answer 1

$refractive \: index \: of \: medium \: a \: with \: respect \: to \: medium \: b \: = _{a}n_{b}$

$_{a} n_{b} = \frac{velocity \: of \: light \: in \: medium \: b}{velocity \: of \: light \: in \: medium \: a}$

$= \frac{200}{300}$

$_{a}n_{b} = \frac{2}{3} \: or \: 0.667$

Answer 2

Answer:

Ray Optics

Explanation:

Refractive Index ( μ ) = Speed of light ( c ) / velocity of light in medium ( v )

★ μ ≈ 1 / v

So ;

Và = 300 km / sec

Vb = 200 km / sec.

» μà / μb = Vb / và

» μà / μb = 200 / 300

» μa / μb = 2 / 3 «

hope it helps you