Question

The velocity of light in water is 2.2 x 108m/s. What is thepolarizing angle of incidence for water surface? Given

speed of light in free space is3 x 108m/s.​

Answer 1

Explanation:

The refractive index of water, μ=

Speed of light in air

Speed of light in air

=

2.2×10

8

3×10

8

=1.36

From Brewster's Law:-

tan i

p

=μ=1.36

∴i

p

=tan

−1

(1.36)=53.74

o

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