the velocity of particle at any time t is givrn by v=(t-2).the average velocity between t=0 to t=3 sec. is
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Velocity v = t-2 given
Average velocity = total distance traveled by the partical /total time taken by the partical
V =dx/dt =t-2
dx =(t-2) dt
Now integrated the both sides of the equation
X = t^2 - 2t
So total distance = X3-X0=9-2*3-0=3
Vavg =3/3=1m/s
... I hope it's help
Average velocity = total distance traveled by the partical /total time taken by the partical
V =dx/dt =t-2
dx =(t-2) dt
Now integrated the both sides of the equation
X = t^2 - 2t
So total distance = X3-X0=9-2*3-0=3
Vavg =3/3=1m/s
... I hope it's help
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