the velocity of particle at time t (in second) is related to its displacement x (in metre)at v =root over 3x+4.the intial velocity of the particle is
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Answer:v=1/V3 ( Here V is used to denote square root )
Explanation:
t = V3 x +4
tV3 -4 / 3 = x
Differentiating x with respect to t ,
v=dx/dt
v= d tV3 -4 /3 / dt = V3/3 = 1/V3
Hope it helps✌
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