Physics, asked by akshaigv887, 1 year ago

The velocity of projection is ( 6i + 8j ) m/s . The horizontal range of the projectile is

(A) 4.9m

(B) 9.6m

(C) 19.6m

(D) 14m

Answers

Answered by azizalasha
0

Answer:

choose → answer (B) 9.6m

Explanation:

ucos∝ = 6

usin∝ - 10t = 8

x = 6t

y = utsin∝ - 5t²

y = 0 at t = usin∝/5 , usin∝ = 8 + 10usin∝/5 , usin∝ = -8

range R = 6usin∝/5 = 48/5 = 9.6 m

choose → answer (B) 9.6m

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