the velocity of projection of a projectile is (6i+8j)m/s.what is he horizontally range of projectile.(g=10m/s^2)
Answers
Answered by
83
Given that,
Velocity of projection v= (6i+8j) m/s
Acceleration due to gravity = 10 m/s²
The x component of velocity is
The y component of velocity is
We need to calculate the horizontal range of projectile
Using formula range
Put the value into the formula
Hence, The horizontal range of projectile is 9.6 m.
Answered by
29
Answer:
9.6 m
Explanation:
velocity along x direction (horizontal direction) = 6 m/s
which is , ucosθ = 6m/s
velocity along y direction (vertical direction) = 8m/s
which is ,usinθ = 8m/s
Range =
substituting the values we get,
Range =
on simplifying we get,
Range = 9.6 m
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