Question

the velocity of projection of a projectile is given by u vector = 5i + 10j then find time of flight ,maximum height and range ​

Answer 1

Answer: Time of flight only depends on Perpendicular velocity or velocity along the net acceleration. Here the only acceleration is g downwards . and the perpendicular velocity is 10j . So time of flight by formula = 2u/g = 2*10/10 = 2 sec

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Answer 2

Given,

the velocity of projection of a projectile is given by u vector = 5i + 10j.

To find: time of flight ,maximum height and range ​

Solution:

Time of flight = (2*u along y-axis) / g = 2*10/10

or, Time of flight = 2 second

Maximum height = (u along y-axis)² /2g = 10*10/2*10

or, Maximum height = 5 m

Range = 2*(u long x-axis)*u along y-axis / g = 2*10*5/10

or, Range = 10 m