Question

The velocity of projection of an oblique projectile is v = 3î + 2j^ in ms^-1. The speed of the projectile at the
highest point of the trajectory is?
​

Answer 1

Answer:

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11th

Physics

Motion in a Plane

Projectile Motion

The velocity of projection ...

PHYSICS

The velocity of projection of oblique projectile is (6

i

+8

j

)ms

−1

. The horizontal range of the projectile is

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ANSWER

v

=6

i

+8

j

Comparing with

v

=v

x

i

+v

y

j

we get

v

x

=6 ms

−1

and v

y

=8 ms

−1

also v

2

=v

x

2

+v

y

2

=36+64=100

or v=10 ms

−1

sinθ=

10

8

and cosθ=

10

6

R=

g

v

2

sin2θ

=

g

2v

2

sinθcosθ

R=2×10×10×

10

8

×

10

6

×

10

1

=9.6 m

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Answer 2

Answer:

zero

Explanation:

at highest point of trajectory velocity becomes zero it regains velocity due to gravity