The velocity of sound in air at room
temperature is 333 m/s. An air column is
33.3 cm in length. Find the frequency of the
fifth overtone in a pipe when it is
1.closed at one end.
2.open at both ends
Answers
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According to your question
given that
velocity of sound (v)=333m/s
length of air column(L)=33.3cm
we know that in closed organ pipe,
the frequency of nth overtone will be
=(2n-3)v/4L
then, for fifth overtone
=(2×5-3)×333/4×33.3×10^-2
=7×333×10^3/4×333
=1450Hz
Now, for open organ pipe it will be
=(n-1)v/2L
=(5-1)×333/2×33.3×10^-2
=4×333×10^3/2×333
=2000Hz
I hope it will be helpful for you.
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