Question

the velocity of sound in gas is 498m/s and in air is 332m/s what is the ratio of wavelength of sound waves in gas to air

Answer 1

Hii friend,

Velocity= velocity of sound in air/velocity of sound in medium.

velocity= 332/498

Since frequency= c/lamda

frequency
$\infty$
1/lamda



velocity=lamda2/lamda1

velocity=498/332

velocity=12/8

Velocity=4/3

:- the ratio is 4:3.

hope this helps you a little!!!

Answer 2

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Wavelength of a wave is the distance between two crests or troughs.

Wavelength is represented by Greek symbol :

$\lambda \: \: lambda$

Now, there is a relationship between velocity, frequency and wavelength of waves. Relationship is :

$\maltese \: v = n\lambda$

This relation says velocity of a wave is product of its Frequency and wavelength.

Now Let's say , Velocity of sound in gas be v1 and wavelength be lambda1, frequency will be same in both cases.

Now we can say :-.

$\maltese \: v_1 = n\lambda_1$

Now for water let velocity be v2 and wavelength be lambda2.

Thus we can say : -

$\maltese \: v_2 = n\lambda_2$

After putting the values we can say :-

For gas :-

$498 = n\lambda_1$

For water :-

$332 = n\lambda_2$

Now if we find ratio of these velocities we get :

$\frac{498}{332} = \frac{n\lambda_1}{n\lambda_2}$

$\frac{498}{332} = \cancel \frac{n}{n} \times \frac{\lambda_1}{\lambda_2}$

$\cancel \frac{498}{332} = \frac{\lambda_1}{\lambda_2}$

$\frac{4}{3} = \frac{\lambda_1}{\lambda_2}$

Therefore we get ratio of wavelength of sound in gas to water is 4 : 3.

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BY SCIVIBHANSHU

THANK YOU

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