Question

the velocity of sound waves decreases from 340 metre per second to 240 metre per second on passing from one medium to another if the wavelength in the first medium is 3m what is the wavelength in the second medium​

Answer 1

Answer:

let's

v1 be 340m/s

v2 be 240m/s

lambda 1 be 3m

lambda 2=?

velocity of sound wave 1=frequency*lamda1

340m/s=frequency*3

frequency=340/3

frequency=113.3

frequency never changes when medium changes.

lambda 2=velocity of sound /frequency

=240/113.3

= 2.118

=2.12m

Answer 2

The wavelength in the second medium is 4.25 meters.

As per the question given,

The velocity of sound waves (v) is inversely proportional to the wavelength (λ), so the product of velocity and wavelength remains constant.

v1 λ1 = v2 λ2

Given that the velocity of sound waves decreases from 340 m/s to 240 m/s, and the wavelength in the first medium (λ1) is 3 m.

v1 = 340 m/s

v2 = 240 m/s

λ1 = 3 m

To find the wavelength in the second medium (λ2), we can use the above formula and solve for λ2:

v1 λ1 = v2 λ2

340 x 3 = 240 x λ2

λ2 = (340 x 3) / 240

λ2 = 4.25 m

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