the velocity of the car becomes 5 m/s in 1st 10 second .in next two minutes its velocity becomes 18 km/hr.then what will be the acceleration of the car
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velocity of the car in first ten seconds = 5 m/s
time taken = 10 s
velocity of the car in next two minutes = 18 km/hr
time taken = 2 min
lets convert both time into sec and as well as km to m
18 x 1000
3600
= 5 m/s
time taken = 2 min = 2 x 60 = 120 s
So we have time and initial velocity as 5 m/s
and final velocity as 5 m/s
but we have two time
so adding the both time we get
10+120
130
therefore by using the equation of acceleration
a=(v-u)/t
a=(5-5)/130
a=0/130
a=0
so there was no acceleration in the speed
hence the acceleration is o m/s²
time taken = 10 s
velocity of the car in next two minutes = 18 km/hr
time taken = 2 min
lets convert both time into sec and as well as km to m
18 x 1000
3600
= 5 m/s
time taken = 2 min = 2 x 60 = 120 s
So we have time and initial velocity as 5 m/s
and final velocity as 5 m/s
but we have two time
so adding the both time we get
10+120
130
therefore by using the equation of acceleration
a=(v-u)/t
a=(5-5)/130
a=0/130
a=0
so there was no acceleration in the speed
hence the acceleration is o m/s²
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