Question

The velocity of the particle which is falling freely from rest in the first ,second and third seconds are in the ratio
(a) 1:2:3
(b) 1:3:5
(c) 1:4:9
(d) none of these​

Answer 1

Answer:

The ratio of ratio of the distances travelled by a freely falling body in first, second, and third second of its fall . So, the ratio of distances traveled by a freely falling body in first, second, and third second will be 1:3:5.

Explanation:

hence option b is correct..!

Answer 2

Explanation:

Initial velocity of the body  u=0

Distance covered in tth second,  St=u+21g(2t−1)

∴  St=0+21g(2t−1)=21g(2t−1)

Distance travelled in first second i.e. t=1,  S1=21g(2×1−1)=21g

Distance travelled in 2nd second i.e. t=2,  S2=21g(2×2−1)=23g

Distance travelled in third second i.e. t=3,  S3=21g(2×3−1)=25g

⟹  S1:S2:S3=1:3:5