the velocity of train changes from 25m/s to 5m/s,when it covers a distance of 600m. find the acceleration of the train . find the time taken for the same.
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Answer:
v=5m/s
u=25m/s
s=600m
v^2=u^2+2as
5^2=25^2+2×a×600
25=625+1200a
25-625=1200a
-600/1200=a
a=-1/2=-0.5m/s^2
v=u+at
5=25+(-0.5×t)
5-25=-0.5t
-20=-0.5t
-20/-0.5=t
t=40s
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