The velocity of water depends on their wavelength,density of water and accleration due to gravity. find the relation between these quantaties by the method of dimensions.
Answers
Answered by
3
Let v = k * λ^a ρ^b g^c
v = [L] [T]⁻¹ λ = [ L] ρ = density = [M] [L]⁻³ g = [ L] [T]⁻²
Hence [L][T]⁻¹ = [M]^b [L]^{a-3b+c} [T]^{-2c}
Comparing the dimensions:
b = 0. c = 1/2 => a = 1/2
So v = k √(gλ)
Read more on Brainly.in - https:Let v = k * λ^a ρ^b g^c
v = [L] [T]⁻¹ λ = [ L] ρ = density = [M] [L]⁻³ g = [ L] [T]⁻²
Hence [L][T]⁻¹ = [M]^b [L]^{a-3b+c} [T]^{-2c}
Comparing the dimensions:
b = 0. c = 1/2 => a = 1/2
So v = k √(gλ)
v = [L] [T]⁻¹ λ = [ L] ρ = density = [M] [L]⁻³ g = [ L] [T]⁻²
Hence [L][T]⁻¹ = [M]^b [L]^{a-3b+c} [T]^{-2c}
Comparing the dimensions:
b = 0. c = 1/2 => a = 1/2
So v = k √(gλ)
Read more on Brainly.in - https:Let v = k * λ^a ρ^b g^c
v = [L] [T]⁻¹ λ = [ L] ρ = density = [M] [L]⁻³ g = [ L] [T]⁻²
Hence [L][T]⁻¹ = [M]^b [L]^{a-3b+c} [T]^{-2c}
Comparing the dimensions:
b = 0. c = 1/2 => a = 1/2
So v = k √(gλ)
Similar questions