Question

The velocity position graph of a particle moving on a straight line is as shown, the graph of acceleration position is best described by?

Answer 1

Answer:

(3) please mark the answer as brainlest.

Answer 2

Hey there, I'm also studying at Aakash!

First find value of acc with eqn a=v×dv/dx

Where v is 8 and dv/dx is slope of lone that is -8/4 = -2 (Minus as it is decreasing)

Now your a come out to be -16 initially, and ZERO at v = 0, as it depends directly!

Thus second graph is correct!

Good Luck for you Preparation dear!