The velocity position graph of a particle moving on a straight line is as shown, the graph of acceleration position is best described by?
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(3) please mark the answer as brainlest.
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Hey there, I'm also studying at Aakash!
First find value of acc with eqn a=v×dv/dx
Where v is 8 and dv/dx is slope of lone that is -8/4 = -2 (Minus as it is decreasing)
Now your a come out to be -16 initially, and ZERO at v = 0, as it depends directly!
Thus second graph is correct!
Good Luck for you Preparation dear!
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