Physics, asked by bambambholejk, 7 months ago

The velocity ratio and efficiency of a
given pulley system have value 4 and 90%
Find M.A of pulley system
How much effort would be needed to lift
a load of 300N?​

Answers

Answered by pranjulsingh882
0

Answer:

here's your answer

Explanation:

M.A.=

Effort

Load

⇒Load=M.A.×Effort

=3.6×300=1080N

Answered by joinaditya6
3

Answer:

VR = 4, դ = 90%

(i) MA = VR x դ%

= 4 x 90/100 = 3.6

(ii) MA = Load/Effort

∴ Effort = Load/MA

= 300/3.6

83.33 N

Explanation:

i think you are satisfied from this answer

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