The velocity ratio and efficiency of a
given pulley system have value 4 and 90%
Find M.A of pulley system
How much effort would be needed to lift
a load of 300N?
Answers
Answered by
0
Answer:
here's your answer
Explanation:
M.A.=
Effort
Load
⇒Load=M.A.×Effort
=3.6×300=1080N
Answered by
3
Answer:
VR = 4, դ = 90%
(i) MA = VR x դ%
= 4 x 90/100 = 3.6
(ii) MA = Load/Effort
∴ Effort = Load/MA
= 300/3.6
83.33 N
Explanation:
i think you are satisfied from this answer
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