Question

the velocity ratio in case of an inclined plane inclined at an angle a to the horizontal and weight being pullef up the inclined plane by vertical effort is​

Answer 1

Answer:

here is your answer

Explanation:

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Answer 2

Answer:

v`/ v = sina

Explanation:

In inclined plane , acceleration = g sina

So from equations of motion ,

v` = u + g sina × t

initial velocity = 0

Hence , v` = g sina × t .........................1)

Now in vertical effort , acceleration = g

So from equations of motion ,

v = u + gt

v = gt..................................………....2)

Hence , from equation 1) and 2) ,

v`/v = g sina × t/ gt

v`/ v = sina.

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