Question

the velocity ratio in case of an inclined plane inclined at angle θ to the horizontal and weight being pulled up the inclined plane by vertical effort is​

Answer 1

Answer:

The velocity ratio in case of an inclined plane inclined at angle 0 to the horizontal and weight being pulled up the inclined plane by vertical effort is. A particle is projected wityh velocity 20 ms-1 at angle 60∘ above horizontal up on an inclined plane having inclination 30∘.

Step-by-step explanation:

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Answer 2

The weight pulled by the inclined plane by vertical effort is sinθ.

The ratio can be given as sin2θ+cos2θ.

• The answer is sinθ because the base of the inclined plane is cosθ.
• Opposite divided by the base is sinθ by trigonometric standard formula.
• The inclined plane is opposite to the direction of the weight being pulled, which is the base.
• We know that the opposite divide by base gives hypotenuse and in this case, we get sinθ.