Math, asked by Rrcool7243, 11 months ago

The velocity ratio of simple screw jack when length of handle is 100mm and pitch of screw is 10 mm

Answers

Answered by bhagyashreechowdhury
1

Given:

The length of handle of the screw jack = 100 mm

The pitch of the screw = 10 mm

To find:

The velocity ratio of a simple screw jack

Solution:

The formula to find the velocity ratio of a simple screw jack is given as,

\boxed{Velocity\:Ratio\:=\:\frac{distance\:moved\:by\:effort}{distance\:moved\:by\:load}\:=\:\frac{2\:\pi\:R}{P}  }

where

R = length of the arm from the center of the screw

P = pitch of the thread of the screw

Now, we will substitute the given values of R = 100 mm and P = 10 mm in the above formula,

Velocity Ratio = \frac{2\:\times\:\frac{22}{7}\:\times\:100 }{10} = \frac{628.57}{10} = \bold{62.857}

Thus, the velocity ratio of simple screw jack is 62.857.

-----------------------------------------------------------------------------------------------

Also View:

A pulley system with a velocity ratio 4 is used to lift a load of 150kgf through a vertical height of 20 m. the effort required is 50kgf in downward direction.

calculate:

distance moved by effort

total no. of pulleys

mechanical advantage

efficiency

https://brainly.in/question/14691461

If a load f 1200 kg is lifted by an effort of 300 kg by a simple machine having velocity ratio of 5 ,then its efficiency is ____

https://brainly.in/question/10450049

Answered by PrathameshGolekar
0

Answer:

Given:

The length of handle of the screw jack = 100 mm

The pitch of the screw = 10 mm

To find:

The velocity ratio of a simple screw jack

Solution:

The formula to find the velocity ratio of a simple screw jack is given as,

\boxed{Velocity\:Ratio\:=\:\frac{distance\:moved\:by\:effort}{distance\:moved\:by\:load}\:=\:\frac{2\:\pi\:R}{P} }

VelocityRatio=

distancemovedbyload

distancemovedbyeffort

=

P

2πR

where

R = length of the arm from the center of the screw

P = pitch of the thread of the screw

Now, we will substitute the given values of R = 100 mm and P = 10 mm in the above formula,

Velocity Ratio = \frac{2\:\times\:\frac{22}{7}\:\times\:100 }{10} = \frac{628.57}{10} = \bold{62.857}

10

7

22

×100

=

10

628.57

=62.857

Thus, the velocity ratio of simple screw jack is 62.857.

-----------------------------------------------------------------------------------------------

Also View:

A pulley system with a velocity ratio 4 is used to lift a load of 150kgf through a vertical height of 20 m. the effort required is 50kgf in downward direction.

calculate:

distance moved by effort

total no. of pulleys

mechanical advantage

efficiency

https://brainly.in/question/14691461

If a load f 1200 kg is lifted by an effort of 300 kg by a simple machine having velocity ratio of 5 ,then its efficiency is ____

https://brainly.in/question/10450049

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