Question

The velocity – time graph below describes a 50 second journey of a car. Calculate the total distance travelled by the car and the maximum acceleration of the car during its 50 second journey. pls no spam answers

Answer 1

Answer:

Distance travelled = 675 m

Max Acceleration = 1.5 m/s²

Explanation:

Concepts

1. Area under speed-time graph represents the distance travelled by the object.

2. Slope of velocity time graph represents the acceleration of the object.

Calculation

Distance travelled

s = area under speed time graph

$= \frac{1}{2} 10.15 + 10. 15 + \frac{1}{2} (15 + 25).10 + \frac{1}{2} .20.25$

$= 5 \times 15 + 10 \times 15 + 20 \times 10 + 10 \times 25$

$75 + 150 + 200 + 250$

$675 \: m$

To find maximum acceleration, let us estimate acceleration at the time intervals (0,10), (10, 20), (20,30), (30,50)

0≤ t < 10 a = slope = 15/10 = 1.5 m/s²

10≤ t < 20 a = 0/10 = 0 m/s²

20 ≤ t < 30 a = 10/10 = 1 m/s²

30 ≤ t < 50 a = -25/20 = -1.25 m/s²

Hence maximum acceleration of the care is 1.5 m/s².

Answer 2

Answer:

Distance travelled = 675 m

Max Acceleration = 1.5 m/s²